Resolve all Placeholders in a Dictionary

Usage

resolveAll(dictionary, ...)

Arguments

dictionary: list with named elements where the element name represents the key and the element value represents the value assigned to the key.
...: additional assignments of the form <key> = <value> that are temporarily added to the dictionary before doing the resolving

Examples

# Define a dictionary in the form of a list
dictionary <- list(
  basedir = "C:/myNicefolder",
  projectdir = "<basedir>/projects/<project_name>",
  inputdir = "<projectdir>/input",
  outputdir = "<projectdir>/output"
)

# Resolve all entries in the dictionary, with different values for the
# placeholder "<project_name> which is undefined in the original dictionary
dictionary.1 <- resolveAll(dictionary, project_name = "project_1")
dictionary.2 <- resolveAll(dictionary, project_name = "project_2")

# Define entries of the dictionary to resolve
keys <- c("inputdir", "outputdir")

# Resolve the entries using the two different dictionaries
resolve(keys, dictionary.1)
#> [1] "C:/myNicefolder/projects/project_1/input" 
#> [2] "C:/myNicefolder/projects/project_1/output"
resolve(keys, dictionary.2)
#> [1] "C:/myNicefolder/projects/project_2/input" 
#> [2] "C:/myNicefolder/projects/project_2/output"